同构 2026-08-26 数学 群论入门 · 06 定义同构 定义映射φ\varphiφ,群GGG的元素一一映射G1G_1G1,∀a,b∈G,(ab)φ=aφbφ\forall a,b \in G, (ab)^{\varphi} = a^{\varphi}b^{\varphi}∀a,b∈G,(ab)φ=aφbφ 称为GGG和G1G_1G1同构 写作G≅G1G \cong G_1G≅G1 同构性质 GGG的单位元eee, G1G_1G1的单位元e1e_1e1, eφ=e1e^{\varphi} = e_1eφ=e1 ∀a∈G,(a−1)φ=(aφ)−1\forall a \in G, (a^{-1})^{\varphi} = (a^{\varphi})^{-1}∀a∈G,(a−1)φ=(aφ)−1 ∀a∈G,ord(a)=ord(aφ)\forall a \in G, ord(a) = ord(a^{\varphi})∀a∈G,ord(a)=ord(aφ) 证明: 设 n=ord(a)n = \mathrm{ord}(a)n=ord(a), m=ord(aφ)m = \mathrm{ord}(a^{\varphi})m=ord(aφ) 由 (an)φ=(aφ)n=e1(a^n)^{\varphi} = (a^{\varphi})^n = e_1(an)φ=(aφ)n=e1 得m∣nm \mid nm∣n (am)φ=e1=φ(e)(a^m)^{\varphi} = e_1 = \varphi(e)(am)φ=e1=φ(e) 由 φ\varphiφ 单射得 am=ea^m = eam=e,故 n∣mn \mid mn∣m 因此 ord(aφ)=m=n\mathrm{ord}(a^{\varphi}) = m = nord(aφ)=m=n ∀a,b∈G,ab=ba ⟹ aφbφ=bφaφ\forall a, b \in G, ab = ba \implies a^{\varphi}b^{\varphi} = b^{\varphi}a^{\varphi}∀a,b∈G,ab=ba⟹aφbφ=bφaφ ∀H≤G ⟺ Hφ≤G1\forall H \le G \iff H^{\varphi} \le G_1∀H≤G⟺Hφ≤G1 ← 群的陪集分解 专栏目录 群的置换表示 →