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同构

定义同构

定义映射φ\varphi,群GG的元素一一映射G1G_1,∀a,b∈G,(ab)φ=aφbφ\forall a,b \in G, (ab)^{\varphi} = a^{\varphi}b^{\varphi}

称为GG和G1G_1同构

写作G≅G1G \cong G_1

同构性质

  1. GG的单位元ee, G1G_1的单位元e1e_1, eφ=e1e^{\varphi} = e_1

  2. ∀a∈G,(a−1)φ=(aφ)−1\forall a \in G, (a^{-1})^{\varphi} = (a^{\varphi})^{-1}

  3. ∀a∈G,ord(a)=ord(aφ)\forall a \in G, ord(a) = ord(a^{\varphi})

    证明:

    设 n=ord(a)n = \mathrm{ord}(a), m=ord(aφ)m = \mathrm{ord}(a^{\varphi})

    由 (an)φ=(aφ)n=e1(a^n)^{\varphi} = (a^{\varphi})^n = e_1 得m∣nm \mid n

    (am)φ=e1=φ(e)(a^m)^{\varphi} = e_1 = \varphi(e)

    由 φ\varphi 单射得 am=ea^m = e,故 n∣mn \mid m

    因此 ord(aφ)=m=n\mathrm{ord}(a^{\varphi}) = m = n

  4. ∀a,b∈G,ab=ba  ⟹  aφbφ=bφaφ\forall a, b \in G, ab = ba \implies a^{\varphi}b^{\varphi} = b^{\varphi}a^{\varphi}

  5. ∀H≤G  ⟺  Hφ≤G1\forall H \le G \iff H^{\varphi} \le G_1